y^2+2y+3=180

Solution for y^2+2y+3=180 equation:

y^2+2y+3=180

We move all terms to the left:

y^2+2y+3-(180)=0

We add all the numbers together, and all the variables

y^2+2y-177=0

a = 1; b = 2; c = -177;
Δ = b2-4ac
Δ = 22-4·1·(-177)
Δ = 712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{712}=\sqrt{4*178}=\sqrt{4}*\sqrt{178}=2\sqrt{178}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{178}}{2*1}=\frac{-2-2\sqrt{178}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{178}}{2*1}=\frac{-2+2\sqrt{178}}{2}
$